/sci/ - Science & Math

E=IR
...

Ohm's law bro.
I = V/R

LRN2OHMSLAW

its flowing this way through it

and because those resistors are on the same rung, you add them to get your equivalent resistor, 6k
then, i = e/r, so
i = 120/6
i = 20

the main goal of circuits like this is to combine the resistors into one.

20mA

I'm just a little confused about your values.
Is 120Vdc the same as 120 Volts?

What does 4k and 2k stand for? Are they resistance?

Another important note:
In series, Rtotal = R1 + R2 + ... +Rn
In parallel, Rtotal = 1/(1/R1 + 1/R2 + ... + Rn)

The resistors are in series, so Rtotal = R1 + R3. Combine the two resistors together and treat them like a single resistor with a new resistance of Rtotal. Then, using, V = iR, calculate the current, i, through the resistor (V is the voltage of the battery).

For objects in series, current is the same through all of them.
For objects in parallel, voltage is the same through all of them

Since we are in series, we know that i for R1 is the same as i for R3, which both equal the i for Rtotal.

>>1931968

oops, for parallel Rtotal = 1/(1/R1 + 1/R2 + ... + 1/Rn)
Forgot that last 1/

>>1931968
Vdc = Voltage direct current. Same thing as V as far as your concerned.

k = kilo = 1000
4k = 4000 ohms
Cool guys don't bother writing ohms when its a resistor. Its a resistor; it resists; in Ohms.

You'll have about 14 mega amps flowing through that baby.